(x^2-5x+6)(1+4x)=0

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Solution for (x^2-5x+6)(1+4x)=0 equation:


Simplifying
(x2 + -5x + 6)(1 + 4x) = 0

Reorder the terms:
(6 + -5x + x2)(1 + 4x) = 0

Multiply (6 + -5x + x2) * (1 + 4x)
(6(1 + 4x) + -5x * (1 + 4x) + x2(1 + 4x)) = 0
((1 * 6 + 4x * 6) + -5x * (1 + 4x) + x2(1 + 4x)) = 0
((6 + 24x) + -5x * (1 + 4x) + x2(1 + 4x)) = 0
(6 + 24x + (1 * -5x + 4x * -5x) + x2(1 + 4x)) = 0
(6 + 24x + (-5x + -20x2) + x2(1 + 4x)) = 0
(6 + 24x + -5x + -20x2 + (1 * x2 + 4x * x2)) = 0
(6 + 24x + -5x + -20x2 + (1x2 + 4x3)) = 0

Combine like terms: 24x + -5x = 19x
(6 + 19x + -20x2 + 1x2 + 4x3) = 0

Combine like terms: -20x2 + 1x2 = -19x2
(6 + 19x + -19x2 + 4x3) = 0

Solving
6 + 19x + -19x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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